LeetCode六月挑战(6.16) Validate IP Address Solution LeetCode468 解题报告
Write a function to check whether an input string is a valid IPv4 address or IPv6 address or neither.
IPv4 addresses are canonically represented in dot-decimal notation, which consists of four decimal numbers, each ranging from 0 to 255, separated by dots (“.”), e.g.,172.16.254.1;
Besides, leading zeros in the IPv4 is invalid. For example, the address 172.16.254.01 is invalid.
IPv6 addresses are represented as eight groups of four hexadecimal digits, each group representing 16 bits. The groups are separated by colons (“:”). For example, the address 2001:0db8:85a3:0000:0000:8a2e:0370:7334 is a valid one. Also, we could omit some leading zeros among four hexadecimal digits and some low-case characters in the address to upper-case ones, so 2001:db8:85a3:0:0:8A2E:0370:7334 is also a valid IPv6 address(Omit leading zeros and using upper cases).
However, we don’t replace a consecutive group of zero value with a single empty group using two consecutive colons (::) to pursue simplicity. For example, 2001:0db8:85a3::8A2E:0370:7334 is an invalid IPv6 address.
Besides, extra leading zeros in the IPv6 is also invalid. For example, the address 02001:0db8:85a3:0000:0000:8a2e:0370:7334 is invalid.
Note: You may assume there is no extra space or special characters in the input string.
1 | Example 1: |
思路
这个题目是考察String的,我们直接根据IPv4和IPv6的格式进行判断即可,或者采用正则表达式。值得注意的是,split函数在分割 . $ | 和 * 等转义字符,必须得加 \\ 。同时分割分数limit应为-1,因为如果最后n位都是切割符,split(“ “)不会继续切分,split(“ “, -1)会继续切分。
Java代码
1 | class Solution { |